[cobalt-users] Raq2 Network IP Address Configuration

["Darryl Hafermalz" <dhafermalz@xxxxxxxxxxxxxx>]

Now that I've gotten my IP issue resolved at the ISP, I'm "peeling" the
onion as I have encountered another problem.

I have been assigned  block of public IP addresses that do not have
traditional 8 bit boundaries.  Here is what I have been assigned -

207.142.10.101 Gateway /29
207.142.10.102 MIA-9012
207.142.10.103 MIA-9012
207.142.10.104 MIA-9012
207.142.10.105 MIA-9012
207.142.10.106 MIA-9012
207.142.10.107 Broadcast

Subnet: 255.255.255.248

However, my Raq thinks the network setup is as follows -

207.142.10.96 Gateway /29
207.142.10.97 MIA-9012
207.142.10.98 MIA-9012
207.142.10.99 MIA-9012
207.142.10.100 MIA-9012
207.142.10.101 MIA-9012
207.142.10.102 Broadcast

Subnet: 255.255.255.248

As a result, I have only one IP address usable for hosts - 102.

The raq is assuming that my 8 address block is in the 12th block of
addresses starting from zero.  Here is an example of what my eth0:0 looks
like -

IPADDR=207.142.10.103
NETWORK=207.142.10.96
NETMASK=255.255.255.248
BROADCAST=207.142.10.103

The gateway address, as set in the gui, is set to 207.142.10.101 which
allows the 102 address to work correctly.

How would I correct this problem if the ISP relegates me to this grouping of
addresses?   If I manually correct the eth0:0 file, there is no improvement
in the situation.

Confusing enough?

Thanks

Darryl L. Hafermalz
West Atlantic Networks