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RE: [cobalt-users] chmod



isn't it as simple as this??? (Hope I got it right :)

O=Owner
G=Group
W=World
r=read, w=write, x=executable permissions.

 O  G   W
rwx rwx rwx
421 421 421
--- --- ---
= 7   7   7
--- --- ---

rw- rw- rw-
420 420 420
--- --- ---
= 6   6   6
--- --- ---

rwx rw- r--
421 420 400
--- --- ---
= 7   6   4
--- --- ---
Therefore...

rw- r-- r--
420 400 400
--- --- ---
= 6   4   4
--- --- ---

Yes - that is correct, 644 :)

But if you think of it as bits making octal #'s you will not get in trouble ... it is the correct way, but of course, whatever is easiest to understand is *really* the right way. But, it is really:
rw- r-- r--
110 100 100 - which is the binary for the *octal* numbers 6 4 4 as per my previously posted chart of binary/octal conversions. An *on* character, r w or x, is a 1 in the position, it is not a 4 in that position.

Jale